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5(2x+3)=3(4+1)-(3x+2)
We move all terms to the left:
5(2x+3)-(3(4+1)-(3x+2))=0
We add all the numbers together, and all the variables
5(2x+3)-(35-(3x+2))=0
We multiply parentheses
10x-(35-(3x+2))+15=0
We calculate terms in parentheses: -(35-(3x+2)), so:We get rid of parentheses
35-(3x+2)
determiningTheFunctionDomain -(3x+2)+35
We get rid of parentheses
-3x-2+35
We add all the numbers together, and all the variables
-3x+33
Back to the equation:
-(-3x+33)
10x+3x-33+15=0
We add all the numbers together, and all the variables
13x-18=0
We move all terms containing x to the left, all other terms to the right
13x=18
x=18/13
x=1+5/13
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