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5(2x+3)=3(x+9)
We move all terms to the left:
5(2x+3)-(3(x+9))=0
We multiply parentheses
10x-(3(x+9))+15=0
We calculate terms in parentheses: -(3(x+9)), so:We get rid of parentheses
3(x+9)
We multiply parentheses
3x+27
Back to the equation:
-(3x+27)
10x-3x-27+15=0
We add all the numbers together, and all the variables
7x-12=0
We move all terms containing x to the left, all other terms to the right
7x=12
x=12/7
x=1+5/7
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