5(2x+3)=36+2x-5

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Solution for 5(2x+3)=36+2x-5 equation: 



5(2x+3)=36+2x-5

We move all terms to the left:

5(2x+3)-(36+2x-5)=0

We add all the numbers together, and all the variables

5(2x+3)-(2x+31)=0

We multiply parentheses

10x-(2x+31)+15=0

We get rid of parentheses

10x-2x-31+15=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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