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5(2x+3)=3x-3(x-4)
We move all terms to the left:
5(2x+3)-(3x-3(x-4))=0
We multiply parentheses
10x-(3x-3(x-4))+15=0
We calculate terms in parentheses: -(3x-3(x-4)), so:We add all the numbers together, and all the variables
3x-3(x-4)
We multiply parentheses
3x-3x+12
We add all the numbers together, and all the variables
12
Back to the equation:
-(12)
10x+3=0
We move all terms containing x to the left, all other terms to the right
10x=-3
x=-3/10
x=-3/10
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