5(2x+3)=4(2+3x)+2(2+3x)

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Solution for 5(2x+3)=4(2+3x)+2(2+3x) equation: 



5(2x+3)=4(2+3x)+2(2+3x)

We move all terms to the left:

5(2x+3)-(4(2+3x)+2(2+3x))=0

We add all the numbers together, and all the variables

5(2x+3)-(4(3x+2)+2(3x+2))=0

We multiply parentheses

10x-(4(3x+2)+2(3x+2))+15=0



We calculate terms in parentheses: -(4(3x+2)+2(3x+2)), so:

4(3x+2)+2(3x+2)

We multiply parentheses

12x+6x+8+4

We add all the numbers together, and all the variables

18x+12

Back to the equation:

-(18x+12)



We get rid of parentheses

10x-18x-12+15=0

We add all the numbers together, and all the variables

-8x+3=0

We move all terms containing x to the left, all other terms to the right

-8x=-3

x=-3/-8

x=3/8

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