5(2x+3)=4(2+3x)+2(2+3x)

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Solution for 5(2x+3)=4(2+3x)+2(2+3x) equation:



5(2x+3)=4(2+3x)+2(2+3x)
We move all terms to the left:
5(2x+3)-(4(2+3x)+2(2+3x))=0
We add all the numbers together, and all the variables
5(2x+3)-(4(3x+2)+2(3x+2))=0
We multiply parentheses
10x-(4(3x+2)+2(3x+2))+15=0
We calculate terms in parentheses: -(4(3x+2)+2(3x+2)), so:
4(3x+2)+2(3x+2)
We multiply parentheses
12x+6x+8+4
We add all the numbers together, and all the variables
18x+12
Back to the equation:
-(18x+12)
We get rid of parentheses
10x-18x-12+15=0
We add all the numbers together, and all the variables
-8x+3=0
We move all terms containing x to the left, all other terms to the right
-8x=-3
x=-3/-8
x=3/8

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