5(2x+3)=4(2x-1)+15

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Solution for 5(2x+3)=4(2x-1)+15 equation: 



5(2x+3)=4(2x-1)+15

We move all terms to the left:

5(2x+3)-(4(2x-1)+15)=0

We multiply parentheses

10x-(4(2x-1)+15)+15=0



We calculate terms in parentheses: -(4(2x-1)+15), so:

4(2x-1)+15

We multiply parentheses

8x-4+15

We add all the numbers together, and all the variables

8x+11

Back to the equation:

-(8x+11)



We get rid of parentheses

10x-8x-11+15=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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