5(2x+3)=4(x-1)+9

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Solution for 5(2x+3)=4(x-1)+9 equation: 



5(2x+3)=4(x-1)+9

We move all terms to the left:

5(2x+3)-(4(x-1)+9)=0

We multiply parentheses

10x-(4(x-1)+9)+15=0



We calculate terms in parentheses: -(4(x-1)+9), so:

4(x-1)+9

We multiply parentheses

4x-4+9

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We get rid of parentheses

10x-4x-5+15=0

We add all the numbers together, and all the variables

6x+10=0

We move all terms containing x to the left, all other terms to the right

6x=-10

x=-10/6

x=-1+2/3

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