5(2x+3)=7(x+6)

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Solution for 5(2x+3)=7(x+6) equation: 



5(2x+3)=7(x+6)

We move all terms to the left:

5(2x+3)-(7(x+6))=0

We multiply parentheses

10x-(7(x+6))+15=0



We calculate terms in parentheses: -(7(x+6)), so:

7(x+6)

We multiply parentheses

7x+42

Back to the equation:

-(7x+42)



We get rid of parentheses

10x-7x-42+15=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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