5(2x+35)=3(x+28)

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Solution for 5(2x+35)=3(x+28) equation: 



5(2x+35)=3(x+28)

We move all terms to the left:

5(2x+35)-(3(x+28))=0

We multiply parentheses

10x-(3(x+28))+175=0



We calculate terms in parentheses: -(3(x+28)), so:

3(x+28)

We multiply parentheses

3x+84

Back to the equation:

-(3x+84)



We get rid of parentheses

10x-3x-84+175=0

We add all the numbers together, and all the variables

7x+91=0

We move all terms containing x to the left, all other terms to the right

7x=-91

x=-91/7

x=-13

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