5(2x+4)-3(4x-6)=2(20-x)

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Solution for 5(2x+4)-3(4x-6)=2(20-x) equation:


Simplifying
5(2x + 4) + -3(4x + -6) = 2(20 + -1x)

Reorder the terms:
5(4 + 2x) + -3(4x + -6) = 2(20 + -1x)
(4 * 5 + 2x * 5) + -3(4x + -6) = 2(20 + -1x)
(20 + 10x) + -3(4x + -6) = 2(20 + -1x)

Reorder the terms:
20 + 10x + -3(-6 + 4x) = 2(20 + -1x)
20 + 10x + (-6 * -3 + 4x * -3) = 2(20 + -1x)
20 + 10x + (18 + -12x) = 2(20 + -1x)

Reorder the terms:
20 + 18 + 10x + -12x = 2(20 + -1x)

Combine like terms: 20 + 18 = 38
38 + 10x + -12x = 2(20 + -1x)

Combine like terms: 10x + -12x = -2x
38 + -2x = 2(20 + -1x)
38 + -2x = (20 * 2 + -1x * 2)
38 + -2x = (40 + -2x)

Add '2x' to each side of the equation.
38 + -2x + 2x = 40 + -2x + 2x

Combine like terms: -2x + 2x = 0
38 + 0 = 40 + -2x + 2x
38 = 40 + -2x + 2x

Combine like terms: -2x + 2x = 0
38 = 40 + 0
38 = 40

Solving
38 = 40

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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