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5(2x+4)=7(3x+5)
We move all terms to the left:
5(2x+4)-(7(3x+5))=0
We multiply parentheses
10x-(7(3x+5))+20=0
We calculate terms in parentheses: -(7(3x+5)), so:We get rid of parentheses
7(3x+5)
We multiply parentheses
21x+35
Back to the equation:
-(21x+35)
10x-21x-35+20=0
We add all the numbers together, and all the variables
-11x-15=0
We move all terms containing x to the left, all other terms to the right
-11x=15
x=15/-11
x=-1+4/11
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