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5(2x+5)-3(4x-5)=2(20-x)
We move all terms to the left:
5(2x+5)-3(4x-5)-(2(20-x))=0
We add all the numbers together, and all the variables
5(2x+5)-3(4x-5)-(2(-1x+20))=0
We multiply parentheses
10x-12x-(2(-1x+20))+25+15=0
We calculate terms in parentheses: -(2(-1x+20)), so:We add all the numbers together, and all the variables
2(-1x+20)
We multiply parentheses
-2x+40
Back to the equation:
-(-2x+40)
-2x-(-2x+40)+40=0
We get rid of parentheses
-2x+2x-40+40=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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