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5(2x+5)=2(5-x)
We move all terms to the left:
5(2x+5)-(2(5-x))=0
We add all the numbers together, and all the variables
5(2x+5)-(2(-1x+5))=0
We multiply parentheses
10x-(2(-1x+5))+25=0
We calculate terms in parentheses: -(2(-1x+5)), so:We get rid of parentheses
2(-1x+5)
We multiply parentheses
-2x+10
Back to the equation:
-(-2x+10)
10x+2x-10+25=0
We add all the numbers together, and all the variables
12x+15=0
We move all terms containing x to the left, all other terms to the right
12x=-15
x=-15/12
x=-1+1/4
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