5(2x+5)=6(x+3/2

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Solution for 5(2x+5)=6(x+3/2 equation: 



5(2x+5)=6(x+3/2

We move all terms to the left:

5(2x+5)-(6(x+3/2)=0

We add all the numbers together, and all the variables

5(2x+5)-(6(+x+3/2)=0

We multiply parentheses

10x-(6(+x+3/2)+25=0

We multiply all the terms by the denominator


10x*2)+25-(6(+x+3=0

Wy multiply elements

20x^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$

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