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5(2x+5)=6(x+3/2)
We move all terms to the left:
5(2x+5)-(6(x+3/2))=0
We add all the numbers together, and all the variables
5(2x+5)-(6(+x+3/2))=0
We multiply parentheses
10x-(6(+x+3/2))+25=0
We multiply all the terms by the denominator
10x*2))-(6(+x+3+25*2))=0
We add all the numbers together, and all the variables
10x*2))-(6(x+53))=0
We add all the numbers together, and all the variables
10x*2))-(6(x=0
Wy multiply elements
20x^2=0
a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{40}=0$
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