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5(2x+6)=28-2(5x-6)
We move all terms to the left:
5(2x+6)-(28-2(5x-6))=0
We multiply parentheses
10x-(28-2(5x-6))+30=0
We calculate terms in parentheses: -(28-2(5x-6)), so:We get rid of parentheses
28-2(5x-6)
determiningTheFunctionDomain -2(5x-6)+28
We multiply parentheses
-10x+12+28
We add all the numbers together, and all the variables
-10x+40
Back to the equation:
-(-10x+40)
10x+10x-40+30=0
We add all the numbers together, and all the variables
20x-10=0
We move all terms containing x to the left, all other terms to the right
20x=10
x=10/20
x=1/2
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