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5(2x+7)(x+7)=0
We multiply parentheses ..
5(+2x^2+14x+7x+49)=0
We multiply parentheses
10x^2+70x+35x+245=0
We add all the numbers together, and all the variables
10x^2+105x+245=0
a = 10; b = 105; c = +245;
Δ = b2-4ac
Δ = 1052-4·10·245
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-35}{2*10}=\frac{-140}{20} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+35}{2*10}=\frac{-70}{20} =-3+1/2 $
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