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5(2x+8)=(6x+12)
We move all terms to the left:
5(2x+8)-((6x+12))=0
We multiply parentheses
10x-((6x+12))+40=0
We calculate terms in parentheses: -((6x+12)), so:We get rid of parentheses
(6x+12)
We get rid of parentheses
6x+12
Back to the equation:
-(6x+12)
10x-6x-12+40=0
We add all the numbers together, and all the variables
4x+28=0
We move all terms containing x to the left, all other terms to the right
4x=-28
x=-28/4
x=-7
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