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5(2x+9)+2(x+11)=3(3x+4)+45
We move all terms to the left:
5(2x+9)+2(x+11)-(3(3x+4)+45)=0
We multiply parentheses
10x+2x-(3(3x+4)+45)+45+22=0
We calculate terms in parentheses: -(3(3x+4)+45), so:We add all the numbers together, and all the variables
3(3x+4)+45
We multiply parentheses
9x+12+45
We add all the numbers together, and all the variables
9x+57
Back to the equation:
-(9x+57)
12x-(9x+57)+67=0
We get rid of parentheses
12x-9x-57+67=0
We add all the numbers together, and all the variables
3x+10=0
We move all terms containing x to the left, all other terms to the right
3x=-10
x=-10/3
x=-3+1/3
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