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5(2x+9)+2x+11=3(3x+4)+46
We move all terms to the left:
5(2x+9)+2x+11-(3(3x+4)+46)=0
We add all the numbers together, and all the variables
2x+5(2x+9)-(3(3x+4)+46)+11=0
We multiply parentheses
2x+10x-(3(3x+4)+46)+45+11=0
We calculate terms in parentheses: -(3(3x+4)+46), so:We add all the numbers together, and all the variables
3(3x+4)+46
We multiply parentheses
9x+12+46
We add all the numbers together, and all the variables
9x+58
Back to the equation:
-(9x+58)
12x-(9x+58)+56=0
We get rid of parentheses
12x-9x-58+56=0
We add all the numbers together, and all the variables
3x-2=0
We move all terms containing x to the left, all other terms to the right
3x=2
x=2/3
x=2/3
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