5(2x+9)=3(10x+40)+

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Solution for 5(2x+9)=3(10x+40)+ equation: 



5(2x+9)=3(10x+40)+

We move all terms to the left:

5(2x+9)-(3(10x+40)+)=0

We multiply parentheses

10x-(3(10x+40)+)+45=0



We calculate terms in parentheses: -(3(10x+40)+), so:

3(10x+40)+

We add all the numbers together, and all the variables

3(10x+40)

We multiply parentheses

30x+120

Back to the equation:

-(30x+120)



We get rid of parentheses

10x-30x-120+45=0

We add all the numbers together, and all the variables

-20x-75=0

We move all terms containing x to the left, all other terms to the right

-20x=75

x=75/-20

x=-3+3/4

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