5(2x-+3)=3(3x+12)

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Solution for 5(2x-+3)=3(3x+12) equation:



5(2x-+3)=3(3x+12)
We move all terms to the left:
5(2x-+3)-(3(3x+12))=0
We add all the numbers together, and all the variables
5(+2x)-(3(3x+12))=0
We multiply parentheses
10x-(3(3x+12))=0
We calculate terms in parentheses: -(3(3x+12)), so:
3(3x+12)
We multiply parentheses
9x+36
Back to the equation:
-(9x+36)
We get rid of parentheses
10x-9x-36=0
We add all the numbers together, and all the variables
x-36=0
We move all terms containing x to the left, all other terms to the right
x=36

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