5(2x-1)(2x+1)=0

Solution for 5(2x-1)(2x+1)=0 equation:

Simplifying
5(2x + -1)(2x + 1) = 0

Reorder the terms:
5(-1 + 2x)(2x + 1) = 0

Reorder the terms:
5(-1 + 2x)(1 + 2x) = 0

Multiply (-1 + 2x) * (1 + 2x)
5(-1(1 + 2x) + 2x * (1 + 2x)) = 0
5((1 * -1 + 2x * -1) + 2x * (1 + 2x)) = 0
5((-1 + -2x) + 2x * (1 + 2x)) = 0
5(-1 + -2x + (1 * 2x + 2x * 2x)) = 0
5(-1 + -2x + (2x + 4x2)) = 0

Combine like terms: -2x + 2x = 0
5(-1 + 0 + 4x2) = 0
5(-1 + 4x2) = 0
(-1 * 5 + 4x2 * 5) = 0
(-5 + 20x2) = 0

Solving
-5 + 20x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 20x2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 20x2 = 0 + 5
20x2 = 0 + 5

Combine like terms: 0 + 5 = 5
20x2 = 5

Divide each side by '20'.
x2 = 0.25

Simplifying
x2 = 0.25

Take the square root of each side:
x = {-0.5, 0.5}