5(2x-1)+2(2x-1)=3(3x-4)-(-2-2x)

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Solution for 5(2x-1)+2(2x-1)=3(3x-4)-(-2-2x) equation: 



5(2x-1)+2(2x-1)=3(3x-4)-(-2-2x)

We move all terms to the left:

5(2x-1)+2(2x-1)-(3(3x-4)-(-2-2x))=0

We add all the numbers together, and all the variables

5(2x-1)+2(2x-1)-(3(3x-4)-(-2x-2))=0

We multiply parentheses

10x+4x-(3(3x-4)-(-2x-2))-5-2=0



We calculate terms in parentheses: -(3(3x-4)-(-2x-2)), so:

3(3x-4)-(-2x-2)

We multiply parentheses

9x-(-2x-2)-12

We get rid of parentheses

9x+2x+2-12

We add all the numbers together, and all the variables

11x-10

Back to the equation:

-(11x-10)



We add all the numbers together, and all the variables

14x-(11x-10)-7=0

We get rid of parentheses

14x-11x+10-7=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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