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5(2x-1)+2x-3=4(x+10)
We move all terms to the left:
5(2x-1)+2x-3-(4(x+10))=0
We add all the numbers together, and all the variables
2x+5(2x-1)-(4(x+10))-3=0
We multiply parentheses
2x+10x-(4(x+10))-5-3=0
We calculate terms in parentheses: -(4(x+10)), so:We add all the numbers together, and all the variables
4(x+10)
We multiply parentheses
4x+40
Back to the equation:
-(4x+40)
12x-(4x+40)-8=0
We get rid of parentheses
12x-4x-40-8=0
We add all the numbers together, and all the variables
8x-48=0
We move all terms containing x to the left, all other terms to the right
8x=48
x=48/8
x=6
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