5(2x-1)+3=6-2(x+10)

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Solution for 5(2x-1)+3=6-2(x+10) equation: 



5(2x-1)+3=6-2(x+10)

We move all terms to the left:

5(2x-1)+3-(6-2(x+10))=0

We multiply parentheses

10x-(6-2(x+10))-5+3=0



We calculate terms in parentheses: -(6-2(x+10)), so:

6-2(x+10)

determiningTheFunctionDomain
-2(x+10)+6

We multiply parentheses

-2x-20+6

We add all the numbers together, and all the variables

-2x-14

Back to the equation:

-(-2x-14)



We add all the numbers together, and all the variables

10x-(-2x-14)-2=0

We get rid of parentheses

10x+2x+14-2=0

We add all the numbers together, and all the variables

12x+12=0

We move all terms containing x to the left, all other terms to the right

12x=-12

x=-12/12

x=-1

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