5(2x-1)+4(5x-2)=19-2(x+12)

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Solution for 5(2x-1)+4(5x-2)=19-2(x+12) equation: 



5(2x-1)+4(5x-2)=19-2(x+12)

We move all terms to the left:

5(2x-1)+4(5x-2)-(19-2(x+12))=0

We multiply parentheses

10x+20x-(19-2(x+12))-5-8=0



We calculate terms in parentheses: -(19-2(x+12)), so:

19-2(x+12)

determiningTheFunctionDomain
-2(x+12)+19

We multiply parentheses

-2x-24+19

We add all the numbers together, and all the variables

-2x-5

Back to the equation:

-(-2x-5)



We add all the numbers together, and all the variables

30x-(-2x-5)-13=0

We get rid of parentheses

30x+2x+5-13=0

We add all the numbers together, and all the variables

32x-8=0

We move all terms containing x to the left, all other terms to the right

32x=8

x=8/32

x=1/4

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