5(2x-1)+7x=2(x-8)

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Solution for 5(2x-1)+7x=2(x-8) equation:



5(2x-1)+7x=2(x-8)
We move all terms to the left:
5(2x-1)+7x-(2(x-8))=0
We add all the numbers together, and all the variables
7x+5(2x-1)-(2(x-8))=0
We multiply parentheses
7x+10x-(2(x-8))-5=0
We calculate terms in parentheses: -(2(x-8)), so:
2(x-8)
We multiply parentheses
2x-16
Back to the equation:
-(2x-16)
We add all the numbers together, and all the variables
17x-(2x-16)-5=0
We get rid of parentheses
17x-2x+16-5=0
We add all the numbers together, and all the variables
15x+11=0
We move all terms containing x to the left, all other terms to the right
15x=-11
x=-11/15
x=-11/15

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