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5(2x-1)+9=4(2x+3)+2x
We move all terms to the left:
5(2x-1)+9-(4(2x+3)+2x)=0
We multiply parentheses
10x-(4(2x+3)+2x)-5+9=0
We calculate terms in parentheses: -(4(2x+3)+2x), so:We add all the numbers together, and all the variables
4(2x+3)+2x
We add all the numbers together, and all the variables
2x+4(2x+3)
We multiply parentheses
2x+8x+12
We add all the numbers together, and all the variables
10x+12
Back to the equation:
-(10x+12)
10x-(10x+12)+4=0
We get rid of parentheses
10x-10x-12+4=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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