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5(2x-1)-5=3(x+2)-x
We move all terms to the left:
5(2x-1)-5-(3(x+2)-x)=0
We multiply parentheses
10x-(3(x+2)-x)-5-5=0
We calculate terms in parentheses: -(3(x+2)-x), so:We add all the numbers together, and all the variables
3(x+2)-x
We add all the numbers together, and all the variables
-1x+3(x+2)
We multiply parentheses
-1x+3x+6
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
10x-(2x+6)-10=0
We get rid of parentheses
10x-2x-6-10=0
We add all the numbers together, and all the variables
8x-16=0
We move all terms containing x to the left, all other terms to the right
8x=16
x=16/8
x=2
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