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5(2x-1)-6x=3(x+2)
We move all terms to the left:
5(2x-1)-6x-(3(x+2))=0
We add all the numbers together, and all the variables
-6x+5(2x-1)-(3(x+2))=0
We multiply parentheses
-6x+10x-(3(x+2))-5=0
We calculate terms in parentheses: -(3(x+2)), so:We add all the numbers together, and all the variables
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
4x-(3x+6)-5=0
We get rid of parentheses
4x-3x-6-5=0
We add all the numbers together, and all the variables
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11
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