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5(2x-1)=14+3(x-2)
We move all terms to the left:
5(2x-1)-(14+3(x-2))=0
We multiply parentheses
10x-(14+3(x-2))-5=0
We calculate terms in parentheses: -(14+3(x-2)), so:We get rid of parentheses
14+3(x-2)
determiningTheFunctionDomain 3(x-2)+14
We multiply parentheses
3x-6+14
We add all the numbers together, and all the variables
3x+8
Back to the equation:
-(3x+8)
10x-3x-8-5=0
We add all the numbers together, and all the variables
7x-13=0
We move all terms containing x to the left, all other terms to the right
7x=13
x=13/7
x=1+6/7
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