5(2x-1)=3(x-4)-5=

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Solution for 5(2x-1)=3(x-4)-5= equation: 



5(2x-1)=3(x-4)-5=

We move all terms to the left:

5(2x-1)-(3(x-4)-5)=0

We multiply parentheses

10x-(3(x-4)-5)-5=0



We calculate terms in parentheses: -(3(x-4)-5), so:

3(x-4)-5

We multiply parentheses

3x-12-5

We add all the numbers together, and all the variables

3x-17

Back to the equation:

-(3x-17)



We get rid of parentheses

10x-3x+17-5=0

We add all the numbers together, and all the variables

7x+12=0

We move all terms containing x to the left, all other terms to the right

7x=-12

x=-12/7

x=-1+5/7

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