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5(2x-1)=3+2(3x+14)
We move all terms to the left:
5(2x-1)-(3+2(3x+14))=0
We multiply parentheses
10x-(3+2(3x+14))-5=0
We calculate terms in parentheses: -(3+2(3x+14)), so:We get rid of parentheses
3+2(3x+14)
determiningTheFunctionDomain 2(3x+14)+3
We multiply parentheses
6x+28+3
We add all the numbers together, and all the variables
6x+31
Back to the equation:
-(6x+31)
10x-6x-31-5=0
We add all the numbers together, and all the variables
4x-36=0
We move all terms containing x to the left, all other terms to the right
4x=36
x=36/4
x=9
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