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5(2x-1)=3-2(4-x)
We move all terms to the left:
5(2x-1)-(3-2(4-x))=0
We add all the numbers together, and all the variables
5(2x-1)-(3-2(-1x+4))=0
We multiply parentheses
10x-(3-2(-1x+4))-5=0
We calculate terms in parentheses: -(3-2(-1x+4)), so:We get rid of parentheses
3-2(-1x+4)
determiningTheFunctionDomain -2(-1x+4)+3
We multiply parentheses
2x-8+3
We add all the numbers together, and all the variables
2x-5
Back to the equation:
-(2x-5)
10x-2x+5-5=0
We add all the numbers together, and all the variables
8x=0
x=0/8
x=0
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