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5(2x-1)=5(2x-4)
We move all terms to the left:
5(2x-1)-(5(2x-4))=0
We multiply parentheses
10x-(5(2x-4))-5=0
We calculate terms in parentheses: -(5(2x-4)), so:We get rid of parentheses
5(2x-4)
We multiply parentheses
10x-20
Back to the equation:
-(10x-20)
10x-10x+20-5=0
We add all the numbers together, and all the variables
15!=0
There is no solution for this equation
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