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5(2x-10)-4=5(x-5)+(1)
We move all terms to the left:
5(2x-10)-4-(5(x-5)+(1))=0
We multiply parentheses
10x-(5(x-5)+1)-50-4=0
We calculate terms in parentheses: -(5(x-5)+1), so:We add all the numbers together, and all the variables
5(x-5)+1
We multiply parentheses
5x-25+1
We add all the numbers together, and all the variables
5x-24
Back to the equation:
-(5x-24)
10x-(5x-24)-54=0
We get rid of parentheses
10x-5x+24-54=0
We add all the numbers together, and all the variables
5x-30=0
We move all terms containing x to the left, all other terms to the right
5x=30
x=30/5
x=6
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