5(2x-10)=3x+7(x-2)-36

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Solution for 5(2x-10)=3x+7(x-2)-36 equation: 



5(2x-10)=3x+7(x-2)-36

We move all terms to the left:

5(2x-10)-(3x+7(x-2)-36)=0

We multiply parentheses

10x-(3x+7(x-2)-36)-50=0



We calculate terms in parentheses: -(3x+7(x-2)-36), so:

3x+7(x-2)-36

We multiply parentheses

3x+7x-14-36

We add all the numbers together, and all the variables

10x-50

Back to the equation:

-(10x-50)



We get rid of parentheses

10x-10x+50-50=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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