5(2x-2)+2(3x+3)=4(x+5)

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Solution for 5(2x-2)+2(3x+3)=4(x+5) equation: 



5(2x-2)+2(3x+3)=4(x+5)

We move all terms to the left:

5(2x-2)+2(3x+3)-(4(x+5))=0

We multiply parentheses

10x+6x-(4(x+5))-10+6=0



We calculate terms in parentheses: -(4(x+5)), so:

4(x+5)

We multiply parentheses

4x+20

Back to the equation:

-(4x+20)



We add all the numbers together, and all the variables

16x-(4x+20)-4=0

We get rid of parentheses

16x-4x-20-4=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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