5(2x-2)+2=10(1x-5)+42

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Solution for 5(2x-2)+2=10(1x-5)+42 equation: 



5(2x-2)+2=10(1x-5)+42

We move all terms to the left:

5(2x-2)+2-(10(1x-5)+42)=0

We add all the numbers together, and all the variables

5(2x-2)-(10(x-5)+42)+2=0

We multiply parentheses

10x-(10(x-5)+42)-10+2=0



We calculate terms in parentheses: -(10(x-5)+42), so:

10(x-5)+42

We multiply parentheses

10x-50+42

We add all the numbers together, and all the variables

10x-8

Back to the equation:

-(10x-8)



We add all the numbers together, and all the variables

10x-(10x-8)-8=0

We get rid of parentheses

10x-10x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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