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5(2x-2)+3(x+1)=2(x+2)
We move all terms to the left:
5(2x-2)+3(x+1)-(2(x+2))=0
We multiply parentheses
10x+3x-(2(x+2))-10+3=0
We calculate terms in parentheses: -(2(x+2)), so:We add all the numbers together, and all the variables
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
13x-(2x+4)-7=0
We get rid of parentheses
13x-2x-4-7=0
We add all the numbers together, and all the variables
11x-11=0
We move all terms containing x to the left, all other terms to the right
11x=11
x=11/11
x=1
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