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5(2x-2)=3(3x+6)
We move all terms to the left:
5(2x-2)-(3(3x+6))=0
We multiply parentheses
10x-(3(3x+6))-10=0
We calculate terms in parentheses: -(3(3x+6)), so:We get rid of parentheses
3(3x+6)
We multiply parentheses
9x+18
Back to the equation:
-(9x+18)
10x-9x-18-10=0
We add all the numbers together, and all the variables
x-28=0
We move all terms containing x to the left, all other terms to the right
x=28
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