5(2x-20)=10(3x+5)

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Solution for 5(2x-20)=10(3x+5) equation: 



5(2x-20)=10(3x+5)

We move all terms to the left:

5(2x-20)-(10(3x+5))=0

We multiply parentheses

10x-(10(3x+5))-100=0



We calculate terms in parentheses: -(10(3x+5)), so:

10(3x+5)

We multiply parentheses

30x+50

Back to the equation:

-(30x+50)



We get rid of parentheses

10x-30x-50-100=0

We add all the numbers together, and all the variables

-20x-150=0

We move all terms containing x to the left, all other terms to the right

-20x=150

x=150/-20

x=-7+1/2

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