5(2x-3)+1+4(3x-5)=3(x+10)(2x+8)+x

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Solution for 5(2x-3)+1+4(3x-5)=3(x+10)(2x+8)+x equation: 



5(2x-3)+1+4(3x-5)=3(x+10)(2x+8)+x

We move all terms to the left:

5(2x-3)+1+4(3x-5)-(3(x+10)(2x+8)+x)=0

We multiply parentheses

10x+12x-(3(x+10)(2x+8)+x)-15-20+1=0

We multiply parentheses ..

-(3(+2x^2+8x+20x+80)+x)+10x+12x-15-20+1=0



We calculate terms in parentheses: -(3(+2x^2+8x+20x+80)+x), so:

3(+2x^2+8x+20x+80)+x

We multiply parentheses

6x^2+24x+60x+x+240

We add all the numbers together, and all the variables

6x^2+85x+240

Back to the equation:

-(6x^2+85x+240)



We add all the numbers together, and all the variables

22x-(6x^2+85x+240)-34=0

We get rid of parentheses

-6x^2+22x-85x-240-34=0

We add all the numbers together, and all the variables

-6x^2-63x-274=0

a = -6; b = -63; c = -274;
Δ = b2-4ac
Δ = -632-4·(-6)·(-274)
Δ = -2607
Delta is less than zero, so there is no solution for the equation

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