5(2x-3)+4(3x-5)+3(3-x)=12

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Solution for 5(2x-3)+4(3x-5)+3(3-x)=12 equation: 



5(2x-3)+4(3x-5)+3(3-x)=12

We move all terms to the left:

5(2x-3)+4(3x-5)+3(3-x)-(12)=0

We add all the numbers together, and all the variables

5(2x-3)+4(3x-5)+3(-1x+3)-12=0

We multiply parentheses

10x+12x-3x-15-20+9-12=0

We add all the numbers together, and all the variables

19x-38=0

We move all terms containing x to the left, all other terms to the right

19x=38

x=38/19

x=2

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