5(2x-3)+7=-12-5(x+1)

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Solution for 5(2x-3)+7=-12-5(x+1) equation: 



5(2x-3)+7=-12-5(x+1)

We move all terms to the left:

5(2x-3)+7-(-12-5(x+1))=0

We multiply parentheses

10x-(-12-5(x+1))-15+7=0



We calculate terms in parentheses: -(-12-5(x+1)), so:

-12-5(x+1)

determiningTheFunctionDomain
-5(x+1)-12

We multiply parentheses

-5x-5-12

We add all the numbers together, and all the variables

-5x-17

Back to the equation:

-(-5x-17)



We add all the numbers together, and all the variables

10x-(-5x-17)-8=0

We get rid of parentheses

10x+5x+17-8=0

We add all the numbers together, and all the variables

15x+9=0

We move all terms containing x to the left, all other terms to the right

15x=-9

x=-9/15

x=-3/5

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