5(2x-3)-(6x-4)=8-7(x-2)

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Solution for 5(2x-3)-(6x-4)=8-7(x-2) equation: 



5(2x-3)-(6x-4)=8-7(x-2)

We move all terms to the left:

5(2x-3)-(6x-4)-(8-7(x-2))=0

We multiply parentheses

10x-(6x-4)-(8-7(x-2))-15=0

We get rid of parentheses

10x-6x-(8-7(x-2))+4-15=0



We calculate terms in parentheses: -(8-7(x-2)), so:

8-7(x-2)

determiningTheFunctionDomain
-7(x-2)+8

We multiply parentheses

-7x+14+8

We add all the numbers together, and all the variables

-7x+22

Back to the equation:

-(-7x+22)



We add all the numbers together, and all the variables

4x-(-7x+22)-11=0

We get rid of parentheses

4x+7x-22-11=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3

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