5(2x-3)-2=5(x-4)+43

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Solution for 5(2x-3)-2=5(x-4)+43 equation: 



5(2x-3)-2=5(x-4)+43

We move all terms to the left:

5(2x-3)-2-(5(x-4)+43)=0

We multiply parentheses

10x-(5(x-4)+43)-15-2=0



We calculate terms in parentheses: -(5(x-4)+43), so:

5(x-4)+43

We multiply parentheses

5x-20+43

We add all the numbers together, and all the variables

5x+23

Back to the equation:

-(5x+23)



We add all the numbers together, and all the variables

10x-(5x+23)-17=0

We get rid of parentheses

10x-5x-23-17=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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