5(2x-3)-3(x-2)=40

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Solution for 5(2x-3)-3(x-2)=40 equation:


Simplifying
5(2x + -3) + -3(x + -2) = 40

Reorder the terms:
5(-3 + 2x) + -3(x + -2) = 40
(-3 * 5 + 2x * 5) + -3(x + -2) = 40
(-15 + 10x) + -3(x + -2) = 40

Reorder the terms:
-15 + 10x + -3(-2 + x) = 40
-15 + 10x + (-2 * -3 + x * -3) = 40
-15 + 10x + (6 + -3x) = 40

Reorder the terms:
-15 + 6 + 10x + -3x = 40

Combine like terms: -15 + 6 = -9
-9 + 10x + -3x = 40

Combine like terms: 10x + -3x = 7x
-9 + 7x = 40

Solving
-9 + 7x = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 7x = 40 + 9

Combine like terms: -9 + 9 = 0
0 + 7x = 40 + 9
7x = 40 + 9

Combine like terms: 40 + 9 = 49
7x = 49

Divide each side by '7'.
x = 7

Simplifying
x = 7

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