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5(2x-3)-4=5(x-2)+36
We move all terms to the left:
5(2x-3)-4-(5(x-2)+36)=0
We multiply parentheses
10x-(5(x-2)+36)-15-4=0
We calculate terms in parentheses: -(5(x-2)+36), so:We add all the numbers together, and all the variables
5(x-2)+36
We multiply parentheses
5x-10+36
We add all the numbers together, and all the variables
5x+26
Back to the equation:
-(5x+26)
10x-(5x+26)-19=0
We get rid of parentheses
10x-5x-26-19=0
We add all the numbers together, and all the variables
5x-45=0
We move all terms containing x to the left, all other terms to the right
5x=45
x=45/5
x=9
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